2(1/3x-12)^2+(5/3x-12)+2=0

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Solution for 2(1/3x-12)^2+(5/3x-12)+2=0 equation: 


x in (-oo:+oo)

2*((1/3)*x-12)^2+(5/3)*x-12+2 = 0

2*(1/3*x-12)^2+(5*x)/3-12+2 = 0

(2*3*(1/3*x-12)^2)/3+(5*x)/3+(-12*3)/3+(2*3)/3 = 0

2*3*(1/3*x-12)^2+5*x-12*3+2*3 = 0

2/3*x^2-43*x-36+6+864 = 0

2/3*x^2-43*x+6+828 = 0

2/3*x^2-43*x+834 = 0

2/3*x^2-43*x+834 = 0

2/3*x^2-43*x+834 = 0

DELTA = (-43)^2-(2/3*4*834)

DELTA = -375

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

x belongs to the empty set

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